Percentage Compound of Oxygen

In: Science

Submitted By kta05
Words 970
Pages 4
Percentage of Oxygen in Compound-Stoichiometry/ Catalysis

Page 2
Table of Contents

Introduction Page 3
Experimental Procedure Page 4- 5
Results Page 6-7
Discussion Page 7
References Page 8

Page 3
Introduction
This laboratory the weighting techniques and the use of stoichiometry to calculate percentages of substances were reviewed. To calculate the percent purity of sample, stoichometry relationships were used. In this lab stoichiometric relationship was use to find the percent of oxygen in potassium chlorate and also the percent purity of a sample provided. By definition, Stoichiometry is the quantitative relationship amongst elements in a compound to reactant ratio during a chemical reaction. Potassium chlorate (KClO₃), like many other oxygen composing compounds, is decomposed well by heat. Essentially there is an endothermic reaction that by the aid of a catalyst and heat will produce potassium chloride and oxygen. This equation looks as follows:
KClO₃sMnO₂heat2KCls+3O₂(g)
This process can happen without the presence of manganese dioxide (MnO₂), but it will take a very long time. Instead, MnO₂ is used as the catalyst to expedite the heating temperature and does not contribute to the overall oxygen output

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Experimental procedure First, obtain two clean and dry 25x200mm Pyrex test tubes and label the test tubes #1 and #2 respectively. Following the labels, add a pinch of MnO₂ to the test tube labeled #1. Heat the test tube gently over the Bunsen burner to drive away any moisture that that the manganese dioxide may contain. Place the test tubes on a wire cause and allow the test tubes to cool until it reaches room temperature. Once the test tube is full cooled to room…...

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